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„fungor“ – Versionsunterschied

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[ [[fung]] + [[-or]] ] "etwas ausführen, verwalten, abwickeln, zu Ende bringen ..."   
[[fung]][[-or]] {{lat.}} "etwas [[ausführen]], [[verwalten]], [[abwickeln]], zu Ende bringen ..."   


== <span id="Latin">Latin</span> ==
=== <span id="Etymology">Etymology</span> ===
von uig. <em class="Latnx mention" lang="ine-pro">*[[bʰewg-]]</em> "zu genießen".
von uig. <em class="Latnx mention" lang="ine-pro">*[[bʰewg-]]</em> "zu genießen".


vwdt. m. [[fugiō]]
vwdt. m. ''[[fugiō]]''
 
=== <span id="Pronunciation">Pronunciation</span> ===
 
*<span class="ib-brac">(</span><span class="ib-content">[https://en.wikipedia.org/wiki/Classical_Latin Classical]</span><span class="ib-brac">)</span> [https://en.wiktionary.org/wiki/Wiktionary:International_Phonetic_Alphabet IPA]<sup>([https://en.wiktionary.org/wiki/Appendix:Latin_pronunciation key])</sup>: <span class="IPA">/ˈfun.ɡor/</span>, <span class="IPA">[ˈfʊŋɡɔr]</span>
*<span class="ib-brac">(</span><span class="ib-content">[https://en.wikipedia.org/wiki/Latin_phonology_and_orthography#Ecclesiastical_pronunciation modern Italianate Ecclesiastical]</span><span class="ib-brac">)</span> [https://en.wiktionary.org/wiki/Wiktionary:International_Phonetic_Alphabet IPA]<sup>([https://en.wiktionary.org/wiki/Appendix:Latin_pronunciation key])</sup>: <span class="IPA">/ˈfun.ɡor/</span>, <span class="IPA">[ˈfuŋɡor]</span>


=== <span id="Verb">Verb</span> ===
=== <span id="Verb">Verb</span> ===
<p><span class="headword-line"><strong class="Latn headword" lang="la">fungor</strong> (''present infinitive'' <strong class="Latn" lang="la">[https://en.wiktionary.org/wiki/fungi#Latin fungī]</strong>, ''perfect active'' <strong class="Latn" lang="la">[https://en.wiktionary.org/wiki/functus#Latin fūnctus] sum</strong>)</span>; ''[https://en.wiktionary.org/wiki/Appendix:Latin_third_conjugation third conjugation], [https://en.wiktionary.org/wiki/deponent#English deponent]''</p>
<p><span class="headword-line"><strong class="Latn headword" lang="la">fungor</strong> (''present infinitive'' <strong class="Latn" lang="la">[https://en.wiktionary.org/wiki/fungi#Latin fungī]</strong>, ''perfect active'' <strong class="Latn" lang="la">[https://en.wiktionary.org/wiki/functus#Latin fūnctus] sum</strong>)</span>; ''[https://en.wiktionary.org/wiki/Appendix:Latin_third_conjugation third conjugation], [https://en.wiktionary.org/wiki/deponent#English deponent]''</p>
#etwas ausführen, verwalten, abwickeln, zu Ende bringen, vervollständigen oder beenden, beobachten (mit Ablativ der Aufgabe oder Funktion)
#etwas ausführen, verwalten, abwickeln, zu Ende bringen, vervollständigen oder beenden, beobachten (mit Ablativ der Aufgabe oder Funktion)<span id="Pronunciation">Pronunciation</span>
 
*<span class="ib-brac">(</span><span class="ib-content">[[wikipedia:Classical_Latin|Classical]]</span><span class="ib-brac">)</span> [[wikt:Wiktionary:International_Phonetic_Alphabet|IPA]]<sup>([[wikt:Appendix:Latin_pronunciation|key]])</sup>: <span class="IPA">/ˈfun.ɡor/</span>, <span class="IPA">[ˈfʊŋɡɔr]</span>
==== <span id="Usage_notes">Usage notes</span> ====
*<span class="ib-brac">(</span><span class="ib-content">[[wikipedia:Latin_phonology_and_orthography#Ecclesiastical_pronunciation|modern Italianate Ecclesiastical]]</span><span class="ib-brac">)</span> [[wikt:Wiktionary:International_Phonetic_Alphabet|IPA]]<sup>([[wikt:Appendix:Latin_pronunciation|key]])</sup>: <span class="IPA">/ˈfun.ɡor/</span>, <span class="IPA">[ˈfuŋɡor]</span>
Nutzungshinweise


*The verb <em class="Latn mention" lang="la"><strong class="selflink">fungor</strong></em> and others like it, <em class="Latn mention" lang="la">[https://en.wiktionary.org/wiki/utor#Latin ūtor]</em>, <em class="Latn mention" lang="la">[https://en.wiktionary.org/wiki/fruor#Latin fruor]</em>, <em class="Latn mention" lang="la">[https://en.wiktionary.org/wiki/potior#Latin potior]</em>, <em class="Latn mention" lang="la">[https://en.wiktionary.org/wiki/vescor#Latin vescor]</em>, and their compounds, regularly [https://en.wikipedia.org/wiki/Case_government govern] the ablative case.
# Das Verb ''fungor'' und ähnliche Verben wie ūtor, fruor, potior, vescor und ihre Verbindungen bestimmen regelmäßig den Ablativ.
*In early Latin, <em class="Latn mention" lang="la"><strong class="selflink">fungor</strong></em> governed the accusative case.<sup id="cite_ref-1" class="reference">[https://en.wiktionary.org/wiki/fungor#cite_note-1 [1]]</sup>
# Im frühen Latein beherrschte ''fungor'' den Akkusativ.

Version vom 4. April 2024, 16:13 Uhr

fung-or Vorlage:lat. "etwas ausführen, verwalten, abwickeln, zu Ende bringen ..."

von uig. *bʰewg- "zu genießen".

vwdt. m. fugiō

Verb

fungor (present infinitive fungī, perfect active fūnctus sum); third conjugation, deponent

  1. etwas ausführen, verwalten, abwickeln, zu Ende bringen, vervollständigen oder beenden, beobachten (mit Ablativ der Aufgabe oder Funktion)Pronunciation

Nutzungshinweise

  1. Das Verb fungor und ähnliche Verben wie ūtor, fruor, potior, vescor und ihre Verbindungen bestimmen regelmäßig den Ablativ.
  2. Im frühen Latein beherrschte fungor den Akkusativ.